\newcommand{\dif}{\mathop{}\!\mathrm{d}} \int_{0}^{1}\ln(1+x)\dif x
i\hbar\frac{\partial}{\partial t}\left|\Psi(t)\right>=H\left|\Psi(t)\right>
·
\newcommand{\dif}{\mathop{}\!\mathrm{d}} \int_{0}^{1}\ln(1+x)\dif x
i\hbar\frac{\partial}{\partial t}\left|\Psi(t)\right>=H\left|\Psi(t)\right>
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